Should I serve jury duty when I have no respect for the judge? end; Assigning a value to either the CurrentCustomer property or to a member of the record exposed by the CurrentCustomer property results in the compiler emitting this E2064 error. See the different behaviors in the following code with the explicit getter and setter functions: type TRec = record A: Integer; B: string; end; TForm2 = class(TForm) private FRec : TRec; These temporaries are by design "read-only." This is what you're running into. have a peek here
If you think version "testB" does not compile because InnerRecord is a read-only property, your are *wrong*! and so I redeclare it in a derived class. Delphi 1 and SQL param - left side of = 7. However, you would, of course, have to create and free the object to make sure to prevent memory leaks. http://stackoverflow.com/questions/620506/left-side-cannot-be-assigned-to-for-record-type-properties-in-delphi
end; Therefore, in the mentioned poll, the correct answer is "Versions B and C". Copyright(C) 2009 Embarcadero Technologies, Inc. The only pitfall here is that when you wish to actually retrieve a copy of the record to work with, you will have to something like MyRec := Form1.Rec^ share|improve this
Browse other questions tagged delphi compiler-errors delphi-2009 delphi-xe or ask your own question. Browse other questions tagged delphi records or ask your own question. asked 5 years ago viewed 2002 times active 5 years ago Blog International salaries at Stack Overflow Linked 14 “Left side cannot be assigned to” for record type properties in Delphi If you want to stay with a Record, you have to use an intermediate variable (or the Field variable) or use a WITH statement.
What we have in versions B and C, is a call to "test.InnerRecord" that calls the getter function for the InnerRecord property - so it must be that we are trying asked 7 years ago viewed 11307 times active 2 years ago Blog International salaries at Stack Overflow Linked 3 Delphi “E2064 Left side cannot be assigned to” error appeared when upgrading Consider this, which is semantically equivalent to your example: ... http://docwiki.embarcadero.com/RADStudio/XE6/en/E2064_Left_side_cannot_be_assigned_to_(Delphi) Humans as batteries; how useful would they be?
What if the lead developers abandon Monero, like what happened to Boolberry? BTW the code posted doesn't compile since Record is a reserved word in OP. Or should I go for a workaround? Skip to content Ignore Learn more Please note that GitHub no longer supports old versions of Firefox.
program Solve; var c: Integer = 1; (*Use an initialized variable*) procedure p(var s: string); begin s:= 'changed'; (*Use variable parameter*) end; function f: PChar; begin f:= 'Hello'; (*This is fine https://gist.github.com/2923945 Starting hit points for Arcane Ward Why is the emission curve of Monero so steep? Properties only return or set a value. Properties used without Get/Set methods can only access a single field in the object's data.
share|improve this answer answered Mar 7 '09 at 7:25 Barry Kelly 33.8k472152 add a comment| up vote 4 down vote A solution I frequently use is to declare the property as What are the drawbacks of the US making tactical first use of nuclear weapons against terrorist sites? I really wouldn't suggest to do such swapping via a property anyway.
Examples program Produce; const c = 1; procedure p(const s: string); begin s:= 'changed'; (*<-- Error message here*) end; function f: PChar; begin f:= 'Hello'; (*This is fine - we are Are there any saltwater rivers on Earth? The answers on the question to which you linked provide the explanations even better and provide the solutions (or work-arounds) from which to choose. with Rec do A := ARec.A; // works with original property and with!
file://continue with J, K with increasing index. > end; > and here's where the problem set in... > procedure TDerived.SetRecord(Index:Integer;Value:Integer); > begin > case Index of > 0: Record.I:= Value; file://Error How to print labels from left side to right side (Quick Report) 3. current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. this contact form Sign in to comment Contact GitHub API Training Shop Blog About © 2016 GitHub, Inc.
With objects, this is not a problem because the single field you access is a pointer to data, a method or another object. Thanks anyway. How can we judge the accuracy of Nate Silver's predictions? type PRec = ^TRec; TRec = record A : integer; B : string; end; TForm1 = class(TForm) private FRec : TRec; function GetRec: PRec; procedure SetRec(Value: PRec); public property Rec :
Here how it goes: TRecord=record I, J, K:Integer; end; TBase=class(TPersistent) private FRecord:TRecord; protected property Record:TRecord read FRecord write FRecord; end; ... left side cannot be assigned to ? All of these are illegal. The example assigns to constant parameter, to a constant, and to the result of a function call.
Embed Share Copy sharable URL for this gist. Another thing you can do here is to break out the individual fields of the record as properties on the containing class: ... It is not a reference or a pointer to the record so : Testing.TestRecord.I := 10; // error is same as calling a function like this: Testing.getTestRecord().I := 10; //error (i Hot Network Questions Speed and Velocity in German Three riddles, one solution Why doesn't Rey sell BB8?
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